2x^2+4x+9x+80=180

Solution for 2x^2+4x+9x+80=180 equation:

2x^2+4x+9x+80=180

We move all terms to the left:

2x^2+4x+9x+80-(180)=0

We add all the numbers together, and all the variables

2x^2+13x-100=0

a = 2; b = 13; c = -100;
Δ = b2-4ac
Δ = 132-4·2·(-100)
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{969}}{2*2}=\frac{-13-\sqrt{969}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{969}}{2*2}=\frac{-13+\sqrt{969}}{4}
$